In a triangle abc, side ab 7√2 BC = 17, the angle ABD is 45. Find AC.

univerkov | December 26, 2020 | education

Here you need to use the cosine theorem since we know two sides and an angle:
AC ^ 2 = AB ^ 2 + BC ^ 2-2AB * BCcos (abc) = 98 + 289-68√2 * 2 / √2 = 387-136 = 251
Ac = √251

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