In a triangle ABC, the angle B = 62 *, and the angle A is 20 * less than the angle C.

In a triangle ABC, the angle B = 62 *, and the angle A is 20 * less than the angle C. You need to find the degree measure of A, and also find out the type of triangle.

Given triangle ABC.

It is known:

Angle B = 62 °;

Angle A = Angle C – 20 °;

Find corner C.

Let the angle C be equal to x. Then we make an equation and find this angle.

60 + x + x – 20 = 180, since the sum of all angles is 180 °.

60 – 20 + 2 * x = 180;

40 + 2 * x = 180;

2 * x = 180 – 40;

2 * x = 140;

x = 140/2;

x = 70;

This means that the angle C is 70 °.

Let us find what the angle A is equal to, if it is less by 20 ° than the angle C.

70 ° – 20 ° = 50 °.

Answer: Angle A = 50 °.

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