In a triangle ABC, the angle B = 90 degrees CD is the bisector of the triangle, the angle BDC = 70 degrees

In a triangle ABC, the angle B = 90 degrees CD is the bisector of the triangle, the angle BDC = 70 degrees A) find the angles of the triangle ACD b) compare the segments AD and CD

The BCD triangle is rectangular, the sum of its acute angles is 90, then the angle BCD = 90 – 70 = 20.

CD is the bisector of the angle ACB, then the angle ACD = BCD = 20.

The ADC angle is adjacent to the BDC angle, then the ADC angle = 180 – 70 = 110.

Angle DАС = 180 – АDС – АСD = 180 – 110 – 20 = 50.

The length of the CD side is greater than AD since the angle DАС> АСD.

Answer: The angles of the triangle ACD are equal to 20, 50, 110, the segment CD> AD.