In a triangle abc, the angle b is 90 degrees, bd is the height, ab = 2bd, prove that 3ac = 4ad.

Angle BAC-30 degrees, TC BD = 1 / 2AB
angle DBC = 30
AC = AD + DC, DC = 1 / 2BC and BC = 1/2 AC means DC = 1 / 4AC
AD = AC-DC
AD = AC-1 / 4AC
AD = (4AC-AC) / 4
4AD = 3AC



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