In a triangle ABC, the angle BAC is 34, find the angle adjacent to the outer corner of the triangle at vertex B if AB = AC.
| June 24, 2021 | education
Since AB = AC, the triangle ABC is isosceles with the base BC. Then the angle ABC = ACB.
The sum of the inner angles of the triangle is 180, then the angle ABC = ACB = (180 – BAC) / 2 = (180 – 34) / 2 = 73.
The outer corner of the triangle is the angle DBA = (180 – 73) = 107.
Adjacent to the outer corner is the inner corner ABC.
Answer: The angle adjacent to the outer corner at vertex B is 73.
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