In a triangle ABC, the angle is C = 60 degrees, AB = √ 3/5. Find the radius of the circumscribed circle of triangle ABC.

By the condition of the problem, the side and the angle opposite the given side are known. Let’s use the sine theorem and write the equality:
2R = AB / sin C = AB / sin 60 ° = √3 / 5 / √3 / 2 = √3 / 5 * 2 / √3 = 2/5 = 0.4.
R = 2R / 2 = 0.4 / 2 = 0.2.
Answer: the radius of the circumscribed circle is 0.2.



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