In a triangle ABC, the angle is C 90, BC = 4. The area of the triangle is 18. Find tgB.

tgB = AC / BC
BC = 4, you need to find the AC side
Ac-?
The area of a right-angled triangle is half the product of the legs
S = AC * BC / 2
4/2 * AC = 4
hence :
AC = 9
tgB = 9/4 = 2.25



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