In a triangle ABC, the angle is C = 90 degrees. AC = 12, cosine of angle B = 0.6. Find the BC side.

1. Cosine ∠B = BC / AB.

BC / AB = 0.6.

BC = 0.6AB.

2. Calculate the length of the hypotenuse AB using the Pythagorean theorem:

AB² = AC² + BC².

AB² = 12² + (0.6AB) ² = 144 + 0.64AB²

0.36AB² = 144.

AB² = 144 / 0.36.

AB = √144 / 0.36 = 15 units.

3. Calculate the length of the BC leg using the Pythagorean theorem:

BC = √AB² – AC² = √15² – 12² = √225 – 144 = √81 = 9 units.

Answer: the length of the BC leg is 9 units.



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