In a triangle ABC, the angle is C 90 sin a = √7 / 4. Find cos B.

Let’s use the following formula:
sin² A + cos² A = 1;
Let’s transform:
cos²A = 1 – sin²A;
Substitute the values and find cos²A:
cos²A = 1 – (√7 / 4) ²;
cos²A = 1 – 7/16;
cos²A = 9/16;
Find the value of cos A:
cos A = √ (9/16);
cos A = 3/4;
cos A = 0.75.
Answer: cos A = 0.75



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