In a triangle ABC, the angle is C = 90 tgA = √51 / 7 Find sinB

univerkov | June 9, 2021 | education

Since tgА = √51 / 7, then let the length of the leg BC = √51 * X cm, and the leg AC = 7 * X cm.

Then, by the Pythagorean theorem, AB ^ 2 = BC ^ 2 + AC ^ 2 = 51 * X ^ 2 + 49 * X ^ 2 = 100 * X ^ 2.

AB = 10 * X.

Then SinB = AC / AB = 7 * X / 10 * X = 0.7.

Answer: SinB = 0.7.

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