In a triangle ABC, the angle is C-line, sin of angle A = 4√11 divided by 15. Find sinB-?
| August 9, 2021 | education
1. The angles of a right-angled triangle satisfy the ratio: A + B = 90 °. Or B = 90o – A.
2. Therefore Sin (B) = Sin (90о – A) = Cos (A).
3. From the relation [Sin (A)] ^ 2 + [Cos (A)] ^ 2 = 1 we obtain: Sin (B) = √ {1 – [Sin (A)] ^ 2}.
4. [Sin (A)] ^ 2 = (4 * √11 / 15) ^ 2 = 16 * 11/225.
5.1 – 16 * 11/225 = 49/225.
6. Sin (B) = √ (49/225) = 7/15.
Answer: Sin (B) = 7/15.
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