In a triangle ABC, the angle with a straight line, BC = 6, sine A is 0.6. Find AB.
| May 27, 2021 | education
1) It is known that BC = 6;
sin A = 0.6.
Find AB.
2) sin a = BC / AB;
From here we express the formula AB.
AB * sin a = BC;
AB = BC / sin a.
3) Substitute the known value of the leg and the value of the acute angle, and calculate the hypotenuse of a right-angled triangle.
AB = BC / sin a = 6 / 0.6 = 60/6 = 10;
Answer: AB = 10.
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