In a triangle ABC, the angle with a straight line, BC = 6, sine A is 0.6. Find AB.

1) It is known that BC = 6;

sin A = 0.6.

Find AB.

2) sin a = BC / AB;

From here we express the formula AB.

AB * sin a = BC;

AB = BC / sin a.

3) Substitute the known value of the leg and the value of the acute angle, and calculate the hypotenuse of a right-angled triangle.

AB = BC / sin a = 6 / 0.6 = 60/6 = 10;

Answer: AB = 10.

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