In a triangle ABC, where AB = CB, the angle C is 65 °. The height AH is drawn from the top A. Find the corner BAH.

1. Triangle ABC is isosceles, since the lateral sides AB and BC are equal.

2. Angle A is equal to angle C as angles at the base of an isosceles triangle:

Angle A = angle C = 65 °.

3. Triangle АСН is rectangular, since АН is height.

4. We calculate the value of the angle СAН, based on the fact that the total value of all angles of the triangle is 180:

СAН angle = 180 ° – 65 ° – 90 ° = 25 °.

5. We calculate the value of the angle BAН:

Angle BAН = 65 ° – 25 ° = 40 °.

Answer: the angle BAН is 40 °.