In a triangle MNC, MN = NK, MK = √ (2), angle M = zo degrees, MA is the bisector. Find MA

From the condition it is known that in a triangle the least squares, МН = НК, that is, the triangle given to us is isosceles, MK = √2, it is also known that the angle М = 30 °, MA is the bisector drawn from the angle bisector M.

Let’s calculate its length.

MA -?

Decision:

Since MA is a bisector and the bisector bisects the angle, the angle NMA = angle AMK = 30/2 = 15 °.

Hence:

angle MAK = 180 ° – (15 ° + 30 °) = 135 °.

Let’s apply the sine theorem:

MK / sin 135 ° = MA / sin 30 °;

MA = MK * sin 30 ° / sin 135 °;

MA = 0.99.