In a triangle mnk, the angle m is 28 degrees and the angle n is 1.5 times greater

In a triangle mnk, the angle m is 28 degrees and the angle n is 1.5 times greater than the angle m. Find the outer corner of the triangle at the vertex K.

Let us find the angle N of this triangle, if it is known that it is 1.5 times greater than the angle M, the degree measure of which is 28 °.
Angle N = 28 ° * 1.5 = 42 °
Further, you can find the third corner K of the triangle, and then adjacent to it, which is external at the vertex K.
Or use the fact that in a triangle the degree measure of the outer angle is equal to the sum of two other inner angles that are not adjacent to it. We get:
Outside angle K = angle M + angle N = 28 ° + 42 ° = 70 °.
Answer: the degree measure of the external angle at the vertex K is 70 °.