In a triangle, one of the internal angles is 30 degrees and the second angle is twice the third. find the corners of the triangle.

1. Let’s denote the third inner corner of the triangle as the variable x.

2. Then the second inner corner of the triangle will be 2x degrees.

3. Knowing that, according to the theorem on the sum of the angles of a triangle, this sum is equal to 180 degrees, we compose an equation and find the second (2x) and third (x) angles:

2x + x + 30 = 180;

3x = 150;

x = 50;

2x = 2 * 50 = 100.

Answer: The second inner corner of the triangle is 100 °, the third inner corner of the triangle is 50 °.