In a triangle, one of the sides is 10, the other is 12, and the angle between them is 30 °. Find the area of the triangular.
| August 29, 2021 | education
Given: ABC – triangle, AB = 10, AC = 12, angle A = 30 degrees.
Find: S =?
Solution: The area of a triangle is equal to half of the product of its two sides by the sine of the angle between them: S = 1/2 * AB * AC * Sin of angle A.
Substitute the values: S = 1/2 * 10 * 12 * Sin 30 degrees,
S = 1/2 * 10 * 12 * 1/2 = 30.
Answer: S = 30.
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