In a triangle, one of the sides is 12 and the other is 16 and the sine of the angle between them is one fourth

In a triangle, one of the sides is 12 and the other is 16 and the sine of the angle between them is one fourth, find the area of the triangle.

It is known in the triangle:
One side = 12;
Other side = 16;
The sine of the angle between them = 1/4.
Let’s find the area of the triangle.
Decision:
The area of a triangle is half the product of the side and sine of the angle between them.
S = 1/2 * 12 * 16 * 1/4 = 12 * 16/4 = 12 * 4 = 10 * 4 + 2 * 4 = 40 + 8 = 48;
Answer: S = 48.