In a triangle, one of the sides is 16, the other is 16√3, and the angle between them is 60. Find the area of the triangle.

1. A, B, C – the vertices of the triangle. AB = 16 units. BC = 16√3 units of measurement.

∠В = 60 °. AH – the height drawn to the side of the aircraft. S is the area of the triangle ABC.

2. AH: AB = sine ∠B = sine 60 ° = √3 / 2.

AH = AB x √3 / 2 = 16 x √3 / 2 = 8√3 units of measurement.

3. S = BC / 2 x AH = 16√3 / 2 x 8√3 = 192 units of measurement².

Answer: S = 92 units of measurement².