In a triangle, one of the sides is 28, the other is 17√3, and the angle between them is 60. Find the area.

1. A, B, C – the vertices of the triangle. Angle B = 60 °. AB = 28 units of measurement, BC = 17√3 units of measurement.

2. From the top A we draw the height AH.

3. We calculate its length through the sine of the angle B of the triangle ABN, in which AH is the leg, located opposite the angle B, AB is the hypotenuse:

sine of angle B = AH / AB.

AH = AB x √3 / 2 = 28 x √3 / 2 = 14√3 units.

4. The area of the triangle ABC = BC x AН: 2 = 17√3 x 14√3: 2 = 714: 2 = 357 units ^ 2.

Answer: the area of the triangle ABC = 357 units of measurement ^ 2.