In a triangle, one of the sides is 29 cm, and the second is divided by the point of contact

In a triangle, one of the sides is 29 cm, and the second is divided by the point of contact of the circle inscribed in the triangle into segments of 24 and 1 cm, starting from the end of the first side. Find the perimeter of the triangle.

We mark the points of tangency of the circle with the sides of the triangle by points K, L, M.

Since the circle inscribed in the triangle divides the sides of the triangle into 3 pairs of equal segments, then CК = СL = 24 cm, MV = LВ = 1 cm, AK = AM.

Determine the size of the segment AK.

AK = AC – СK = 29 – 24 = 5 cm, then the AM length is also 5 cm.

Determine the lengths of all sides.

AC = 29 cm.

AB = 5 + 1 = 6 cm.

BC = 24 + 1 = 25 cm.

Ravs = 29 + 6 + 25 = 60 cm.

Answer: The perimeter of triangle ABC is 60 cm.



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