In a triangle, one side and two adjacent corners are given. find the other two sides and

In a triangle, one side and two adjacent corners are given. find the other two sides and its third corner: side b = 30; alpha = 50 degrees; gamma = 45 degrees

Determine the value of the unknown angle ABC. = 30 *

Angle ABC = 180 – BAC – BCA = 180 – 45 – 50 = 850.

We apply the sine theorem for a triangle and determine the lengths of the sides of the triangle.

AC / SinABC = AB / SinACB = BC / SinBAC.

AB = AC * SinACB / SinABC = 30 * 0.766 / 0.99 = 23.21 cm.

BC = AC * SinBAC / SinABC = 30 * 0.707 / 0.99 = 21.42 cm.

Answer: Angle ABC is 850, side AB is 23.21 cm, side BC is 21.42 cm.



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