In a triangle, one side is 36 cm, the other is 4 cm smaller, and the third is x cm larger than the first side.
In a triangle, one side is 36 cm, the other is 4 cm smaller, and the third is x cm larger than the first side. Find the perimeter of the triangle. Make up expressions to solve the problem and find its values at x = 4 and = 8.
Find the length of the second side of this triangle.
According to the condition of the problem, the first side of this triangle is 36 cm, and the second side is 4 cm less, therefore, the length of the second side of this triangle is 36 – 4 = 32 cm.
Let’s write down the length of the third side of this triangle.
According to the condition of the problem, the third side is x cm larger than the first side, therefore, the length of the third side of this triangle is 36 + x cm.
We find the perimeter p of a given triangle as the sum of all its sides:
p = 36 + 32 + 36 + x = 104 + x.
For x = 4, the perimeter p is equal to:
h = 104 + x = 104 + 4 = 108 cm.
When x = 8, the perimeter p is equal to:
h = 104 + 8 = 104 + 8 = 112 cm.