In a triangle, the height BH divides the side AM in half and is equal to 5 cm. The perimeter of triangle ABH is 15 cm

In a triangle, the height BH divides the side AM in half and is equal to 5 cm. The perimeter of triangle ABH is 15 cm. Find the perimeter of triangle ABM.

Triangle ABM.
The height BH divides the side AM into two equal parts AH = HM, so the height BH is also the median, therefore the triangle ABM is isosceles (by property).
Therefore triangles ABH and BHM are equal, therefore the perimeter of triangle BHM is also equal to 15. The perimeter of triangle ABM is 30 cm.
Answer: 30 cm



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