In a triangle, the large side is 16 cm, and the difference between the other two sides is 0.4 dm.

In a triangle, the large side is 16 cm, and the difference between the other two sides is 0.4 dm. What are the sides of a triangle if its perimeter is 0.38 m?

It is known:

In a triangle, the largest side is 16 cm;
The difference between the other two sides is 0.4 dm.
The perimeter is 0.38 m.
Let’s define the sides of the triangle.

Let x be the second side and y the third side.

x – y = 0.4 dm;

x = 0.4 dm + y;

The perimeter is the sum of all sides. Let’s make an equation and find the unknown value.

P = a + b + c;

0.38 m = 16 cm + x + y;

0.38 m = 16 cm + 0.4 dm + y + y;

0.38 m = 16 * 0.01 m + 0.4 * 0.1 m + 2 * y;

0.38 m = 0.16 m + 0.04 m + 2 * y;

0.38 m = 0.2 m + 2 * y;

2 * y = 0.38 – 0.2;

2 * y = 0.18 m;

y = 0.09 m;

2) Find x.

x = 0.4 dm + 0.09 m = 0.04 + 0.09 m = 0.13 m.

Answer: the sides of the triangle are 0.09 m and 0.13 m.