In a uniform electric field, an electron moves with an acceleration of 3.2 * 10

In a uniform electric field, an electron moves with an acceleration of 3.2 * 10 to the 13th power of m / s squared. Determine the field strength if the mass of the electron is 9.1 * 10 to -31 power of kg.

a = 3.2 * 10 ^ 13 m / s2.

m = 9.1 * 10 ^ -31 kg.

q = 1.6 * 10 ^ -19 Cl.

E -?

According to 2 Newton’s law, the force F, which acts on a body, is equal to the product of the body’s mass m by its acceleration a: F = m * a.

An electrostatic force F acts on a charged particle in an electric field, which is determined by the formula: F = q * E, where q is the charge of the particle, E is the strength of the electric field.

m * a = q * E.

E = m * a / q.

E = 9.1 * 10 ^ -31 kg * 3.2 * 10 ^ 13 m / s2 / 1.6 * 10 ^ -19 Cl = 182 V / m.

Answer: the electric field strength will be E = 182 V / m.