In a uniform electric field, the distance between two points lying on the same line of force is 50 cm, and the potential difference
| November 20, 2020 | education
In a uniform electric field, the distance between two points lying on the same line of force is 50 cm, and the potential difference between them is 100 V. Determine the field strength.
Given: E = 50 V / m U = 10 V
Find: d-?
Solution: Relationship of tension and voltage E = U / d d – distance between points E = U / d => d = U / E d = 10/50 = 0.2 (m)
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