In a uniform electric field with a strength of 2 N / C, a charge of 3 C moves along the lines of force of the field at a distance of 0.5 m.

In a uniform electric field with a strength of 2 N / C, a charge of 3 C moves along the lines of force of the field at a distance of 0.5 m. The work of the forces of the electric field in moving the charge is equal to?

To calculate the magnitude of the work of the electric field forces, we will use the formula (we take into account that the indicated charge moves along the field lines of force): A = F * S = E * q * S.

Variables: E – field strength (E = 2 N / C); q – charge (q = 3 C); S – movement of the specified charge (S = 0.5 m).

Let’s calculate: A = E * q * S = 2 * 3 * 0.2 = 3 J.

Answer: The forces of the electric field, according to the calculation, did the work in 3 J.