In a uniform electric field with a strength of 8 * 10 ^ 3 V / m, a particle with a charge of 10 ^ 5 C

| August 18, 2021 | education

In a uniform electric field with a strength of 8 * 10 ^ 3 V / m, a particle with a charge of 10 ^ 5 C and a mass of 10 g began to move. What speed does a particle acquire when it travels a distance of 1m?

E = 8 * 10 ^ 3 V / m.

q = 10 ^ 5 Cl.

m = 10 g = 0.01 kg.

V0 = 0 m / s.

S = 1 m.

V -?

A charged particle in an electric field is affected by a force, the value of which is determined by the formula: F = q * E.

Let’s write 2 Newton’s law: F = m * a.

q * E = m * a.

The acceleration of the body a is expressed by the formula: a = (V ^ 2 – V0 ^ 2) / 2 * S. Since the initial speed is V0 = 0 m / s, the formula will take the form: a = V ^ 2/2 * S.

q * E = m * V ^ 2/2 * S.

V2 = q * E * 2 * S / m.

V = √ (q * E * 2 * S / m).

V = √ (10 ^ 5 C * 8 * 10 ^ 3 V / m * 2 * 1 m / 0.01 kg) = 40 * 10 ^ 4 m / s.

Answer: the particle velocity will become V = 40 * 10 ^ 4 m / s.



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