In a uniform magnetic field, the induction of which is 0.6 T, a conductor with a length of 0.2 m moves

In a uniform magnetic field, the induction of which is 0.6 T, a conductor with a length of 0.2 m moves, a current of 4 A flows through it, the speed of movement is 0.2 m / s and is perpendicular to the magnetic field. Find the work of moving in 10 seconds of movement and the power needed for this movement.

To find the values of the work of moving the specified conductor and the power spent on this movement, we use the formulas: A = Fa * S = (I * B * l) * (V * t) and N = A / t.

Variables: I – current flowing through the specified conductor (I = 4 A); B – field induction (B = 0.6 T); l – conductor length (l = 0.2 m); V is the speed of movement of the conductor (V = 0.2 m / s); t – time (t = 10 s).

Calculation: a) Work: A = I * B * l * V * t = 4 * 0.6 * 0.2 * 0.2 * 10 = 0.96 J;

b) Power: N = A / t = 0.96 / 10 = 96 * 10-3 W = 96 mW.

Answer: To move the indicated conductor, we performed a work of 0.96 J; the required power is 96 mW.