In a uniform magnetic field with an induction of 0.1 T perpendicular to the induction lines there is a conductor 70 cm long.

In a uniform magnetic field with an induction of 0.1 T perpendicular to the induction lines there is a conductor 70 cm long. A current of 70 A flows through it. Determine the force acting on the conductor.

B = 0.1 T.

∠α = 90.

L = 70cm = 0.7m.

I = 70 A.

Fump -?

The ampere force Famp acts on the conductor through which the electric current flows in a uniform magnetic field, the value of which is determined by the formula: Famp = I * B * L * sinα, where I is the current in the conductor, B is the magnetic induction of the field, L is the active conductor length, ∠α is the angle between the direction of the current and the magnetic induction.

Since the conductor is located perpendicular to the magnetic induction of the field, then ∠α = 90.

sin90 = 1.

Fump = I * B * L.

Famp = 70 A * 0.1 T * 0.7 m = 4.9 N.

Answer: Ampere force Famp = 4.9 N. acts on a conductor in a magnetic field.