In a uniform magnetic field with an induction of 0.25 T, a conductor with a length of 10 cm and a mass of 40 g is located.

In a uniform magnetic field with an induction of 0.25 T, a conductor with a length of 10 cm and a mass of 40 g is located. The magnetic induction lines are perpendicular to the conductor. How much current must flow through the conductor so that it is in equilibrium in a magnetic field?

B = 0.25 T.
L = 10 cm = 0.1 m.
m = 40 g = 0.04 kg.
g = 9.8 m / s2.
∠α = 90 °.
I -?
Since the conductor is in a state of equilibrium, the effect of forces on it is compensated. On a conductor with a current in a magnetic field, Ampere force Famp acts vertically upward, and gravity Ft vertically downward.
Fump = Ft.
Famp = I * B * L * sinα.
Fт = m * g.
I * B * L * sinα = m * g.
I = m * g / B * L * sinα.
I = 0.04 kg * 9.8 m / s2 / 0.25 T * 0.1 m * sin90 ° = 15.68 A.
Answer: the current in the conductor should be I = 15.68 A.