In a uniform magnetic field with an induction of 0.25 T, there is a straight conductor 1.4 m long, on which a force of 2.1 N acts.

In a uniform magnetic field with an induction of 0.25 T, there is a straight conductor 1.4 m long, on which a force of 2.1 N acts. Determine the angle between the conductor and the direction of the magnetic field induction vector if the voltage at the ends of the conductor is 24 V, and its resistance is 2 ohms.

F = ILB * sin a, where L is the length of the conductor, B is the magnetic field induction, and is the angle between the induction vector and the direction of the current.
We find the current in the conductor according to Ohm’s law:
I = U / R.
F = (ULB * sina) / R;
sin a = FR / ULB = (2.1 N * 2 Ohm) / (24 V * 1.4 m * 0.25 T) = 0.5;
a = arcsin 0.5 = 30 °.
Answer: 30 °.