In a uniform magnetic field with an induction of 0.5 T, there is a 15 cm long straight conductor through

In a uniform magnetic field with an induction of 0.5 T, there is a 15 cm long straight conductor through which a current of 4A flows. A force of 0.15N acts on the conductor. Determinant of the angle alpha between the directions of the current and the vector of magnetic induction.

To find the angle between the direction of the current and the induction vector, we use the formula: Fa = I * B * l * sinα, whence we express: α = arcsin (Fa / (I * B * l)).

Data: Fa – acting force (Fa = 0.15 N); I – current (I = 4 A); B – field induction (B = 0.5 T); l is the length of the straight conductor (l = 15 cm = 0.15 m).

Let’s calculate: α = arcsin (Fa / (I * B * l)) = arcsin (0.15 / (4 * 0.5 * 0.15)) = arcsin 0.5 = 30º.

Answer: The vector of magnetic induction is located at an angle of 30º to the direction of the current.