In a uniform magnetic field with induction B = 5mT, there is a conductor with a length of l = 2.5 cm

In a uniform magnetic field with induction B = 5mT, there is a conductor with a length of l = 2.5 cm What current (in kA) flows through the conductor if the maximum value of the Ampere force acting on the conductor is F = 1H?

B = 5 mT = 5 * 10-3 T.

Famp = 1 N.

∠α = 900.

L = 2.5 cm = 0.025 m.

I -?

The ampere force Famp acts on the conductor through which the electric current pokes, in a uniform magnetic field, the value of which is determined by the formula: Famp = I * B * L * sinα, where I is the current in the conductor, B is the magnetic induction of the field, L is the active conductor length, ∠α is the angle between the direction of the current and the magnetic induction.

The maximum Ampere force will be at ∠α = 900, the conductor is located perpendicular to the magnetic induction of the field.

sin90 = 1.

I = Famp / B * L.

I = 1 N / 5 * 10 ^ -3 T * 0.025 m = 8000 A.

Answer: the current in the conductor is I = 8000 A.