In a vertical cylindrical vessel partially filled with carbon tetrachloride having a density of 1600 kg / m ^ 3

In a vertical cylindrical vessel partially filled with carbon tetrachloride having a density of 1600 kg / m ^ 3 and immiscible with water, a piece of ice with a mass of 1 kg floats. How and by how much will the height of the carbon tetrachloride level change after all the ice has melted? The bottom area of the vessel is 200 cm ^ 2.

ρtr = 1600 kg / m ^ 3.
m = 1 kg.
ρv = 1000 kg / m ^ 3.
g = 9.8 m / s ^ 2.
S = 200 cm ^ 2 = 0.02 m ^ 2.
Δh -?
The hydrostatic pressure of the liquid at the bottom of the vessel is determined by the formula: P = ρtr * g * h1. Where ρtr is the density of the liquid, g is the acceleration of gravity, h1 is the height of the liquid.
When the ice melts, the pressure on the bottom will add up to the pressure of carbon tetrachloride and water: ρtr * g * h2 + m * g / S.
The pressure on the bottom of the vessel did not change, therefore: ρtr * g * h1 = ρtr * g * h2 + m * g / S.
ρtr * g * (h1 – h2) = m * g / S.
Δh = h1 – h2.
Δh = m * g / S * ρtr * g = m / S * ρtr.
Δh = 1 kg / 0.02 m ^ 2 * 1600 kg / m ^ 3 = 0.03125 m.
Answer: the height of the carbon tetrachloride level decreased by Δh = 0.03125 m.