In a vertical uniform magnetic field, a conductor 0.20 m long and 20.4 g mass is suspended horizontally

In a vertical uniform magnetic field, a conductor 0.20 m long and 20.4 g mass is suspended horizontally on two thin filaments. The magnetic field induction is 0.50 T. At what angle from the vertical will the threads deviate if the current in the conductor is 2.0 A?

Oh: Fa – T * sinα = 0;
Oy: T * cosα – mg = 0;
From the first equation you need to express sin (α), from the second equation cos (α). Then we get the following form of equations:
T * sin (α) = Fa;
T * cos (α) = mg;
Next, you need to do the following:
tg α = Fa / (mg);
tg a = (BLI) / (mg);
tg a = (0.5 * 0.2 * 2) / (0.02 * 10) = 1;
tg 45 ° = 1:
α = 45 °.
Answer: The thread will deflect 45 °.