In a vessel 20 cm high, pour water, the level of which is 2 cm below the edge of the vessel, which is equal

In a vessel 20 cm high, pour water, the level of which is 2 cm below the edge of the vessel, which is equal to the force of water pressure at the bottom of the vessel if the bottom area is 0.01 m ^ 2 atmosphere is not taken into account.

h1 = 20 cm = 0.2 m.

h2 = 2 cm = 0.02 m.

S = 0.01 m ^ 2.

g = 9.8 m / s ^ 2.

ρ = 1000 kg / m ^ 2.

F -?

Let us express the pressure force by the formula: F = P * S, where P is the pressure of the liquid on the bottom, S is the area of the bottom of the vessel.

The hydrostatic pressure of the liquid at the bottom is determined by the formula: P = ρ * g * h. Where ρ is the density of the liquid, g is the acceleration of gravity, h is the height of the liquid.

h = h1 – h2.

The formula for determining the pressure force will take the form: F = S * ρ * g * (h1 – h2).

F = 0.01 m ^ 2 * 9.8 m / s ^ 2 * 1000 kg / m ^ 2 * (0.2 m -0.02 m) = 17.64 N.

Answer: the force of water pressure on the bottom of the vessel is F = 17.64 N.