In a vessel with water taken at a temperature of 0C, 1 kg of water vapor was admitted at a temperature of 100C.

| January 11, 2021 | education

In a vessel with water taken at a temperature of 0C, 1 kg of water vapor was admitted at a temperature of 100C. After some time, the vessel reached a temperature of 20C. What is the mass of water in the vessel at the end of the process?

t1 = 0 0С.
t2 = 100 0С.
m2 = 1 kg.
C = 4200 J / 0С * kg.
q = 2.3 * 106 J / kg.
t = 200 C.
m -?
The final mass of water m will be the sum of the initial mass m1 and the mass of water obtained during the condensation of steam m2: m = m1 + m2.
C * m1 * (t – t1) = q * m2 + C * m2 * (t2 – t) is the heat balance equation.
m1 = (q * m2 + C * m2 * (t2 – t)) / C * (t – t1).
m1 = (2.3 * 106 J / kg * 1 kg + 4200 J / 0C * kg * 1 kg * (100 0C – 20 0C) / 4200 J / 0C * kg * (20 0C – 0 0C) = 31, 4 kg.
m = 1 kg + 31.4 kg = 32.4 kg.
Answer: at the end of the thermal process, the mass of the ox in the vessel will become m = 32.4 kg.



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