In an ABD rhombus with a perimeter of 20 cm, the obtuse angle is 2 times the acute angle.

In an ABD rhombus with a perimeter of 20 cm, the obtuse angle is 2 times the acute angle. Find the perimeter of the triangle ABD.

We take the value of the smaller angle for x, then:

x + 2x = 180

3x = 60

Therefore triangle ABD is equilateral.

Since the perimeter of the rhombus is 20 cm, the side AB will be equal to:

20: 4 = 5 cm.

The perimeter of triangle ABD is:

3 * 5 = 15 cm.

Answer: the desired perimeter is 15 cm.



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