In an acute-angled triangle MPK, the height PH is 5√51 and the side PM is 50. Find the cos of the angle M.

Since PH is height, it is perpendicular to the MK side. This means that the MHP angle is 90.

It follows from this that the triangle MHP is right-angled.

According to the rules for finding the cosine in a right-angled triangle, we get: cos M = MH / PM.

We know the PM length, it remains to calculate the MH length.

It is known that in a right-angled triangle the sum of the squares of the legs is equal to the square of the hypotenuse, which means PM ^ 2 = MH ^ 2 + PH ^ 2.

Substitute the values ​​and get: 50 ^ 2 = MH ^ 2 + (5√51) ^ 2.

MH ^ 2 = 50 ^ 2 – (5√51) ^ 2.

MH ^ 2 = 2500 – 52 * 51.

MH ^ 2 = 2500 – 25 * 51.

MH ^ 2 = 2500 – 1275.

MH ^ 2 = 1225.

MH = 35.

Now we can calculate cos M = 35/50.

cos M = 7/10.

cos M = 0.7.

Answer: cos M = 0.7.



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