In an adult, glaucoma is determined by a dominant autosomal gene. the norm is a recessive trait. what is the probability of the birth of children with an anomaly if one parent is heterozygous for both pairs of genes, and the other is visually normal and homozygous.
Let’s designate the gene that causes the development of glaucoma in humans as G, then the gene that causes normal vision, being presented in homozygous form, will be g.
The heterozygous parent will be Gg, he will suffer from glaucoma and produce G and g germ cells. A parent with normal vision will be gg, the germ cells produced by his body will be of the same type – g.
Possible offspring of this married couple:
children with glaucoma (Gg) – 50%;
children with normal vision (gg) – 50%.
Answer: the probability of birth of children with visual impairment in the presented married couple is 50%.
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