In an alloy of a certain mass, copper, aluminum and manganese are contained in a ratio of 17: 4: 1.

| September 6, 2021 | education

In an alloy of a certain mass, copper, aluminum and manganese are contained in a ratio of 17: 4: 1. In the second alloy of the same mass, in the ratio of 181: 16: 3, one of the metals contains 87.3 kilograms more. What is the mass of the alloy?

Because we know that the second alloy of one of the metals contains 87.3 kg more than the second, then we can proceed as follows:

Suppose we are talking about the second broomstick, then we subtract the difference between the parts of this metal in the first and second alloy: 16h-4h = 12h

This difference will correspond to the mass of 87.3 kg and we can calculate the mass of one part of the metal:
87.3: 12 = 7.275kg

Then the mass of the alloy will be calculated as follows:

(17 + 4 + 1) * 7.275 = 22 * 7.275 = 160.05kg

Answer: 160.05 kg



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