In an aluminum calorimeter, in which there was water weighing 200 g at a temperature of 10 ° C, a copper bar weighing 150 g

| November 19, 2020 | education

In an aluminum calorimeter, in which there was water weighing 200 g at a temperature of 10 ° C, a copper bar weighing 150 g was placed, the temperature of which was 100 ° C. Determine the temperature of the water after thermal equilibrium has been established. calometer weight 100g.

mal = 100 g = 0.1 kg. mwater = 200 g = 0.2 kg. m honey = 150 g = 0.15 kg. Sal = 920 J / kg * “C. Cum = 4200 J / kg *” C. Cmed = 400 J / kg * “С. T1 = 10” С. t2 = 100 “C.
t3 -?
The amount of heat Q1, which is released during the cooling of the copper bar from temperature t2 to temperature t3, goes to heating water Q2 and the calorimeter Q3 from temperature t1 to temperature t3. Q1 = Q2 + Q3. Q1 = Cmed * mmed * (t2 – t3). Q2 = Cv * min * (t3 – t1). Q3 = Cal * mal * (t3 – t1). Med * mmed * (t2 – t3) = Cv * mwater * (t3 – t1) + Sal * mal * (t3 – t1). Smed * mmed * t2 – Smed * mmed * t3 = Cal * mal * t3 – Cal * mal * t1 + Vent * mvolt * t3 – Vent * mvolt * t1. Smed * mmed * t2 + Cal * mal * t1 + Cum * mwater * t1 = Cal * mal * t3 + Cum * mwater * t3 + Cmed * mmed * t3. t3 = (Smed * mmed * t2 + Cal * mal * t1 + Cum * mwater * t) / (Sal * mal + Cum * mwater + Smed * mmed). t3 = (400 J / kg * “C * 0.15 kg * 100” C + 920 J / kg * “C * 0.1 kg * 10” C + 4200 J / kg * “C * 0.2 kg * 10 “C) / (920 J / kg *” C * 0.1 kg + 4200 J / kg * “C * 0.2 kg + 400 J / kg *” C * 0.15 kg) = 15.4 ” FROM.
Answer: the temperature will be set t3 = 15.4 “C.



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