Initial data: U (effective voltage) = 220 V; I (current in an electric oven) = 30 A; t (electric oven operating time) = 1 min or 60 s.
The amount of heat that an electric furnace will give off can be calculated using the formula (Joule-Lenz law): Q = U * I * t.
Let’s calculate the heat: Q = 220 * 30 * 60 = 396 * 10 ^ 3 J = 396 kJ.
Answer: In 1 minute, an electric furnace will release 396 kJ of heat.
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