In an electrical appliance in 45 minutes when a current of 5A passes, 162J work is done.
| September 23, 2021 | education
In an electrical appliance in 45 minutes when a current of 5A passes, 162J work is done. What will be the resistance of the device?
t = 45 min = 2700 s.
I = 5 A.
A = 162 J.
R -?
The work of the current is determined by the Joule-Lenz law: A = I * U * t, where is the current strength, U is the voltage, t is the time of passage of the current.
U = I * R – Ohm’s law.
A = I ^ 2 * R * t.
R = A / I ^ 2 * t.
R = 162 J / (5 A) ^ 2 * 2700 s = 0.0024 Ohm.
Answer: the resistance of the electrical device is R = 0.0024 Ohm.
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