In an electrical circuit with a current source with an EMF of 15V and an internal resistance of 2 ohms.
| June 20, 2021 | education
In an electrical circuit with a current source with an EMF of 15V and an internal resistance of 2 ohms. What is the short circuit current.
To find out the magnitude of the short-circuit current. in the presented circuit, we apply the formula: Ic.z. = ε / r, where ε is the EMF of the source (ε = 15 V); r is the internal resistance of the circuit (r = 2 ohms).
Let’s calculate: Ic.z. = ε / r = 15/2 = 7.5 A.
Answer: In the presented circuit, the short-circuit current, according to the calculation, is 7.5 A.
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