In an equilateral triangle ABC, bisectors AN and BL are drawn, which intersect at point O

In an equilateral triangle ABC, bisectors AN and BL are drawn, which intersect at point O, then the angles of the triangle AOF will be equal.

Since, by condition, triangle ABC is equilateral, then all its internal angles are equal to 60.

The bisectors of the angles of an equilateral triangle are also its medians and heights, then the triangle AOF is rectangular, and the angle OAF = BAC / 2 = 60/2 = 30.

The sum of the acute angles of a right-angled triangle is 90, then the angle AOF = (90 – 30) = 60.

Answer: The angles of the triangle AOF are 30, 60, 90.