In an equilibried triangle ABC AB = BC = 61, and the base AC = 22. Find the length of the median BM.

Since the triangle ABC, by the condition, is a preceded, then his median BM also has its height, then the triangles ABM and CBM are rectangular, and am = cm = AC / 2 = 22/2 = 11 cm.

Then in the rectangular triangle ABM on the Pythagore Theorem, we define the length of the BM category.

BM ^ 2 = AB ^ 2 – AM ^ 2 = 61 ^ 2 – 11 ^ 2 = 3721 – 121 = 360.

BM = 60 cm.

Answer: The length of the median BM is equal to 60 cm.