In an ideal heat engine operating on a carnot cycle, the temperature of the heater is 500K and the temperature

In an ideal heat engine operating on a carnot cycle, the temperature of the heater is 500K and the temperature of the refrigerator is 27 degrees. Determine the efficiency of this engine.

Given:
T1 = 500 ° K,
t2 = 27 ° C;
To find:
η -?
The efficiency of a heat engine operating according to the Carnot cycle can be found using the following formula:
η = 100% * (T1 – T2) / T1;
The temperature of the refrigerator should be taken according to the absolute temperature scale:
T2 = t2 + 273 ° = 300 ° K;
We find:
η = (500 – 300) * 100% / 500 = 40%.